Element: getElementsByTagName() method


目录

{{ APIRef("DOM") }}

The Element.getElementsByTagName() method returns a live {{domxref("HTMLCollection")}} of elements with the given tag name.

All descendants of the specified element are searched, but not the element itself. The returned list is live, which means it updates itself with the DOM tree automatically. Therefore, there is no need to call Element.getElementsByTagName() with the same element and arguments repeatedly if the DOM changes in between calls.

When called on an HTML element in an HTML document, getElementsByTagName lower-cases the argument before searching for it. This is undesirable when trying to match {{Glossary("camel_case", "camel-cased")}} SVG elements (such as <linearGradient>) in an HTML document. Instead, use {{ domxref("Element.getElementsByTagNameNS()") }}, which preserves the capitalization of the tag name.

Element.getElementsByTagName is similar to {{domxref("Document.getElementsByTagName()")}}, except that it only searches for elements that are descendants of the specified element.

Syntax

getElementsByTagName(tagName)

Parameters

Return value

A live {{domxref("HTMLCollection")}} of elements with a matching tag name, in the order they appear. If no elements are found, the HTMLCollection is empty.

Examples

// Check the status of each data cell in a table
const table = document.getElementById("forecast-table");
const cells = table.getElementsByTagName("td");

for (const cell of cells) {
  const status = cell.getAttribute("data-status");
  if (status === "open") {
    // Grab the data
  }
}

Specifications

{{Specifications}}

Browser compatibility

{{Compat}}


版本号 #2
由 壳壳虫 创建于 2026-10-31 03:27:53 UTC
由 壳壳虫 更新于 2026-10-31 03:27:53 UTC